What is the general solution for 5sin(2t)=0 ?

The general solution for 5sin(2t)=0 is t=pin,t= pi/2+pin

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5sin(2t)=0

5 sin (2 t) = 0

t = πn, t = \frac{π}{2} + πn

Solution steps

5 sin (2 t) = 0

Divide both sides by

5

sin (2 t) = 0

General solutions for

sin (2 t) = 0

2 t = 0 + 2 πn, 2 t = π + 2 πn

Solve

2 t = 0 + 2 πn : t = πn

Solve

2 t = π + 2 πn : t = \frac{π}{2} + πn

t = πn, t = \frac{π}{2} + πn

3 tan (3 x) + 3 = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

2 tan (θ) + 4 = tan (θ) + 5

x, sin (x) = \frac{4}{5}

tan (x) = \frac{- 25}{\frac{- 80 - 50}{2}}

4 cos^{2} (A) - 3 = 0

What is the general solution for 5sin(2t)=0 ?
The general solution for 5sin(2t)=0 is t=pin,t= pi/2+pin