What is the general solution for 2tan(θ)+4=tan(θ)+5 ?

The general solution for 2tan(θ)+4=tan(θ)+5 is θ= pi/4+pin

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2tan(θ)+4=tan(θ)+5

2 tan (θ) + 4 = tan (θ) + 5

θ = \frac{π}{4} + πn

Solution steps

2 tan (θ) + 4 = tan (θ) + 5

Solve by substitution

tan (θ) = 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn

x, sin (x) = \frac{4}{5}

tan (x) = \frac{- 25}{\frac{- 80 - 50}{2}}

4 cos^{2} (A) - 3 = 0

\frac{sin ( 4 2 ^{\circ} )}{6.25} = \frac{sin ( x )}{9}

\frac{tan ( x ) + cot ( x )}{csc ( x )} = cos (x)

What is the general solution for 2tan(θ)+4=tan(θ)+5 ?
The general solution for 2tan(θ)+4=tan(θ)+5 is θ= pi/4+pin