What is the general solution for -2sin(t)=-sqrt(2) ?

The general solution for -2sin(t)=-sqrt(2) is t= pi/4+2pin,t=(3pi)/4+2pin

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-2sin(t)=-sqrt(2)

- 2 sin (t) = - 2

t = \frac{π}{4} + 2 πn, t = \frac{3 π}{4} + 2 πn

Solution steps

- 2 sin (t) = - 2

Divide both sides by

- 2

sin (t) = \frac{2}{2}

General solutions for

sin (t) = \frac{2}{2}

t = \frac{π}{4} + 2 πn, t = \frac{3 π}{4} + 2 πn

x, r^{2} = sin (2 x)

3 cos (3 t) = 0

2 cos (x) - 1 = 0, 0 \leq x \leq 2 π

18 cos (x) + 9 sin (2 x) = 0

sin (x) = \frac{5}{29}

What is the general solution for -2sin(t)=-sqrt(2) ?
The general solution for -2sin(t)=-sqrt(2) is t= pi/4+2pin,t=(3pi)/4+2pin