What is the general solution for cos(θ)sin(θ)=0 ?

The general solution for cos(θ)sin(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin,θ=2pin,θ=pi+2pin

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cos(θ)sin(θ)=0

cos (θ) sin (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

Solution steps

cos (θ) sin (θ) = 0

Solving each part separately

cos (θ) = 0 or sin (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

6 cos (6 x - \frac{π}{6}) + 3 = 0

2 sin^{2} (x) = \frac{1}{2}

4 cos (x) - 1 = 2 sin (x) tan (x)

sin (3 x + 1 0^{\circ}) = cos (x + 2 0^{\circ})

tan (θ) = \frac{300}{400}

What is the general solution for cos(θ)sin(θ)=0 ?
The general solution for cos(θ)sin(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin,θ=2pin,θ=pi+2pin