What is the general solution for cot(2x)=-1,(0,2pi) ?

The general solution for cot(2x)=-1,(0,2pi) is x=(3pi)/8 ,x=(7pi)/8 ,x=(11pi)/8 ,x=(15pi)/8

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cot(2x)=-1,(0,2pi)

cot (2 x) = - 1, (0, 2 π)

x = \frac{3 π}{8}, x = \frac{7 π}{8}, x = \frac{11 π}{8}, x = \frac{15 π}{8}

Solution steps

cot (2 x) = - 1, (0, 2 π)

General solutions for

cot (2 x) = - 1

2 x = \frac{3 π}{4} + πn

Solve

2 x = \frac{3 π}{4} + πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{3 π}{8} + \frac{πn}{2}

Solutions for the range

(0, 2 π)

x = \frac{3 π}{8}, x = \frac{7 π}{8}, x = \frac{11 π}{8}, x = \frac{15 π}{8}

(sin (x) + 2) (tan (x) - 2) = 0

sec^{2} (x) + 4 sec (x) - 12 = 0

sin (θ) = - 1, 0^{\circ} \leq θ < 36 0^{\circ}

3 cos^{2} (x) + sin (x) + 1 = 0

2 sin^{2} (\frac{1}{2} x) + C = 2 cos (\frac{x}{2}) sin (\frac{x}{2}) + C

What is the general solution for cot(2x)=-1,(0,2pi) ?
The general solution for cot(2x)=-1,(0,2pi) is x=(3pi)/8 ,x=(7pi)/8 ,x=(11pi)/8 ,x=(15pi)/8