What is the general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi ?

Q: What is the general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi ?

The general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi is x= pi/2

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3sin^2(x)-6sin(x)=-3,0<= x<= 2pi

Solution

3 sin^{2} (x) - 6 sin (x) = - 3, 0 \leq x \leq 2 π

Solution

x = \frac{π}{2}

Degrees

x = 9 0^{\circ}

Solution steps

3 sin^{2} (x) - 6 sin (x) = - 3, 0 \leq x \leq 2 π

Solve by substitution

3 sin^{2} (x) - 6 sin (x) = - 3

Let:

sin (x) = u

3 u^{2} - 6 u = - 3

3 u^{2} - 6 u = - 3 : u = 1

3 u^{2} - 6 u = - 3

Move

3

to the left side

3 u^{2} - 6 u = - 3

Add

3

to both sides

3 u^{2} - 6 u + 3 = - 3 + 3

Simplify

3 u^{2} - 6 u + 3 = 0

3 u^{2} - 6 u + 3 = 0

Solve with the quadratic formula

3 u^{2} - 6 u + 3 = 0

Quadratic Equation Formula:

For

a = 3, b = - 6, c = 3

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 3 = 0

(- 6)^{2} - 4 \cdot 3 \cdot 3

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2}

= 6^{2} - 4 \cdot 3 \cdot 3

Multiply the numbers:

4 \cdot 3 \cdot 3 = 36

= 6^{2} - 36

6^{2} = 36

= 36 - 36

Subtract the numbers:

36 - 36 = 0

= 0

u_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 3}

u = \frac{- ( - 6 )}{2 \cdot 3}

\frac{- ( - 6 )}{2 \cdot 3} = 1

\frac{- ( - 6 )}{2 \cdot 3}

Apply rule

- (- a) = a

= \frac{6}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{6}{6}

Apply rule

\frac{a}{a} = 1

= 1

u = 1

The solution to the quadratic equation is:

u = 1

Substitute back

u = sin (x)

sin (x) = 1

sin (x) = 1

sin (x) = 1, 0 \leq x \leq 2 π : x = \frac{π}{2}

sin (x) = 1, 0 \leq x \leq 2 π

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{2}

Combine all the solutions

x = \frac{π}{2}

Popular Examples

1+sin(pi*t)= 3/2

1 + sin (π \cdot t) = \frac{3}{2}

-cos(x)=sin^2(x)-1

- cos (x) = sin^{2} (x) - 1

csc(x)= 5/2

csc (x) = \frac{5}{2}

csc(x)= 5/4

csc (x) = \frac{5}{4}

3cos(2θ)=9cos(θ)-6

3 cos (2 θ) = 9 cos (θ) - 6

Frequently Asked Questions (FAQ)

What is the general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi ?
The general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi is x= pi/2