What is the general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi ?

The general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi is x= pi/2

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3sin^2(x)-6sin(x)=-3,0<= x<= 2pi

3 sin^{2} (x) - 6 sin (x) = - 3, 0 \leq x \leq 2 π

x = \frac{π}{2}

Solution steps

3 sin^{2} (x) - 6 sin (x) = - 3, 0 \leq x \leq 2 π

Solve by substitution

sin (x) = 1

sin (x) = 1, 0 \leq x \leq 2 π : x = \frac{π}{2}

Combine all the solutions

x = \frac{π}{2}

1 + sin (π \cdot t) = \frac{3}{2}

- cos (x) = sin^{2} (x) - 1

csc (x) = \frac{5}{2}

csc (x) = \frac{5}{4}

3 cos (2 θ) = 9 cos (θ) - 6

What is the general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi ?
The general solution for 3sin^2(x)-6sin(x)=-3,0<= x<= 2pi is x= pi/2