What is the general solution for tan^2(x)-sec(x)+1=0 ?

The general solution for tan^2(x)-sec(x)+1=0 is x=2pin

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tan^2(x)-sec(x)+1=0

tan^{2} (x) - sec (x) + 1 = 0

x = 2 πn

Solution steps

tan^{2} (x) - sec (x) + 1 = 0

Rewrite using trig identities

- sec (x) + sec^{2} (x) = 0

Solve by substitution

sec (x) = 1, sec (x) = 0

sec (x) = 1 : x = 2 πn

sec (x) = 0 :

No Solution

Combine all the solutions

x = 2 πn

sin (2 y) = 0

7 sin^{2} (θ) - 15 sin (θ) + 8 = 0

sin (5 t) = 0

cos (x) = 0, - π \leq x \leq π

sin^{2} (x) + cos (x) = 2

What is the general solution for tan^2(x)-sec(x)+1=0 ?
The general solution for tan^2(x)-sec(x)+1=0 is x=2pin