What is the general solution for sin(5t)=0 ?

The general solution for sin(5t)=0 is t=(2pin)/5 ,t= pi/5+(2pin)/5

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sin(5t)=0

sin (5 t) = 0

t = \frac{2 πn}{5}, t = \frac{π}{5} + \frac{2 πn}{5}

Solution steps

sin (5 t) = 0

General solutions for

sin (5 t) = 0

5 t = 0 + 2 πn, 5 t = π + 2 πn

Solve

5 t = 0 + 2 πn : t = \frac{2 πn}{5}

Solve

5 t = π + 2 πn : t = \frac{π}{5} + \frac{2 πn}{5}

t = \frac{2 πn}{5}, t = \frac{π}{5} + \frac{2 πn}{5}

cos (x) = 0, - π \leq x \leq π

sin^{2} (x) + cos (x) = 2

sin (θ) = - \frac{4}{5}, \frac{7 π}{2} \leq θ < 4 π, cos (2 θ)

cos (2 x) - 2 sin^{2} (x) - sin (x) = 1

- 8 sin (θ) = - 3

What is the general solution for sin(5t)=0 ?
The general solution for sin(5t)=0 is t=(2pin)/5 ,t= pi/5+(2pin)/5