What is the general solution for 4+sin(a)=3sin^2(a) ?

The general solution for 4+sin(a)=3sin^2(a) is a=(3pi)/2+2pin

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4+sin(a)=3sin^2(a)

4 + sin (a) = 3 sin^{2} (a)

a = \frac{3 π}{2} + 2 πn

Solution steps

4 + sin (a) = 3 sin^{2} (a)

Solve by substitution

sin (a) = \frac{4}{3}, sin (a) = - 1

sin (a) = \frac{4}{3} :

No Solution

sin (a) = - 1 : a = \frac{3 π}{2} + 2 πn

Combine all the solutions

a = \frac{3 π}{2} + 2 πn

x, cos (2 x) - cos (x) = 0

tan^{2} (x) + 2 tan (x) - 1 = 0

sin (3 x) = \frac{1}{2}, 0 \leq x \leq 2 π

x, sin (x + y) + sin (x - y) = 1

cos (2 x) = sin (x - \frac{π}{4})

What is the general solution for 4+sin(a)=3sin^2(a) ?
The general solution for 4+sin(a)=3sin^2(a) is a=(3pi)/2+2pin