What is the general solution for -(2sqrt(3))/3 =sec(θ) ?

The general solution for -(2sqrt(3))/3 =sec(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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-(2sqrt(3))/3 =sec(θ)

- \frac{2 3}{3} = sec (θ)

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

- \frac{2 3}{3} = sec (θ)

Switch sides

sec (θ) = - \frac{2 3}{3}

General solutions for

sec (θ) = - \frac{2 3}{3}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

1 sin (3 0^{\circ}) = 1.7 sin (θ)

sin (x) = \pm \frac{1}{2}

30 = 211.49 - 20.96 cosh (0.03291765 x)

tan (θ) = \frac{2}{- 3}

x, z = arcsin (\frac{x y}{x ^{2} + y ^{2}})

What is the general solution for -(2sqrt(3))/3 =sec(θ) ?
The general solution for -(2sqrt(3))/3 =sec(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin