What is the general solution for sin^{(2)}(x)+cos(x)+1=0 ?

The general solution for sin^{(2)}(x)+cos(x)+1=0 is x=pi+2pin

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sin^{(2)}(x)+cos(x)+1=0

sin^{(2)} (x) + cos (x) + 1 = 0

x = π + 2 πn

Solution steps

sin^{(2)} (x) + cos (x) + 1 = 0

Rewrite using trig identities

2 + cos (x) - cos^{2} (x) = 0

Solve by substitution

cos (x) = - 1, cos (x) = 2

cos (x) = - 1 : x = π + 2 πn

cos (x) = 2 :

No Solution

Combine all the solutions

x = π + 2 πn

sin^{2} (θ) = 2 sin (θ)

1 - sin (2 x) = 0

cos (p) - sin (p) = 1

x, y = 2 sin (x)

2 cos (3 x) + cos (2 x) + 1 = 0

What is the general solution for sin^{(2)}(x)+cos(x)+1=0 ?
The general solution for sin^{(2)}(x)+cos(x)+1=0 is x=pi+2pin