What is the general solution for solvefor x,sin(2x)=cos(2x) ?

The general solution for solvefor x,sin(2x)=cos(2x) is x= pi/8+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,sin(2x)=cos(2x)

solve for

x, sin (2 x) = cos (2 x)

x = \frac{π}{8} + \frac{πn}{2}

Solution steps

sin (2 x) = cos (2 x)

Rewrite using trig identities

tan (2 x) = 1

General solutions for

tan (2 x) = 1

2 x = \frac{π}{4} + πn

Solve

2 x = \frac{π}{4} + πn : x = \frac{π}{8} + \frac{πn}{2}

x = \frac{π}{8} + \frac{πn}{2}

cos (x) = \frac{16}{15}

2 sec^{2} (x) - 3 tan (x) = 2

0 = 2 (1 + cos (θ))

\frac{csc ( x )}{5} - 2 = 0

sin (4 y) + sin (6 y) + cos (y) = 0, 0 \leq y \leq \frac{π}{2}

What is the general solution for solvefor x,sin(2x)=cos(2x) ?
The general solution for solvefor x,sin(2x)=cos(2x) is x= pi/8+(pin)/2