What is the general solution for sqrt(2sin(2x))=0 ?

The general solution for sqrt(2sin(2x))=0 is x=pin,x= pi/2+pin

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sqrt(2sin(2x))=0

2 sin (2 x) = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

2 sin (2 x) = 0

Square both sides:

2 sin (2 x) = 0

2 sin (2 x) = 0

Solve

2 sin (2 x) = 0 : sin (2 x) = 0

sin (2 x) = 0

Verify Solutions:

sin (2 x) = 0

True

The solution is

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

2 cos (x) + cos (2 x) = 0

x, - sin (x + y) = 0

cot (θ) = - \frac{1}{2}

sin (2 θ) + sin (θ) + 2 cos (θ) + 1 = 0, 0 \leq θ \leq 2 π

sin^{2} (t) = cos^{2} (t)

What is the general solution for sqrt(2sin(2x))=0 ?
The general solution for sqrt(2sin(2x))=0 is x=pin,x= pi/2+pin