What is the general solution for sin^2(t)=cos^2(t) ?

The general solution for sin^2(t)=cos^2(t) is t= pi/4+pin,t=(3pi)/4+pin

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sin^2(t)=cos^2(t)

sin^{2} (t) = cos^{2} (t)

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

Solution steps

sin^{2} (t) = cos^{2} (t)

Subtract

cos^{2} (t)

from both sides

sin^{2} (t) - cos^{2} (t) = 0

Rewrite using trig identities

- cos (2 t) = 0

Divide both sides by

- 1

cos (2 t) = 0

General solutions for

cos (2 t) = 0

2 t = \frac{π}{2} + 2 πn, 2 t = \frac{3 π}{2} + 2 πn

Solve

2 t = \frac{π}{2} + 2 πn : t = \frac{π}{4} + πn

Solve

2 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{4} + πn

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

cos (x) - sin (x) sin (2 x) = 0

4 sin (x) + 3 cos (x) = 4

sin (θ) - cos (θ) = 0, 0 \leq θ \leq 2 π

3 sec^{2} (θ) - 12 = 5 sec (θ)

3 cos (x) - 3 = cos (x)

What is the general solution for sin^2(t)=cos^2(t) ?
The general solution for sin^2(t)=cos^2(t) is t= pi/4+pin,t=(3pi)/4+pin