What is the general solution for sin(θ)-cos(θ)=0,0<= θ<= 2pi ?

The general solution for sin(θ)-cos(θ)=0,0<= θ<= 2pi is θ= pi/4 ,θ=(5pi)/4

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sin(θ)-cos(θ)=0,0<= θ<= 2pi

sin (θ) - cos (θ) = 0, 0 \leq θ \leq 2 π

θ = \frac{π}{4}, θ = \frac{5 π}{4}

Solution steps

sin (θ) - cos (θ) = 0, 0 \leq θ \leq 2 π

Rewrite using trig identities

tan (θ) - 1 = 0

Move

1

to the right side

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{4}, θ = \frac{5 π}{4}

3 sec^{2} (θ) - 12 = 5 sec (θ)

3 cos (x) - 3 = cos (x)

sin (x) - 1 = - cos (x)

36 cos (2 x) = 0

2 sin^{2} (θ) + sin (θ) = 0, 0 \leq θ < 2 π

What is the general solution for sin(θ)-cos(θ)=0,0<= θ<= 2pi ?
The general solution for sin(θ)-cos(θ)=0,0<= θ<= 2pi is θ= pi/4 ,θ=(5pi)/4