What is the general solution for 3cos^2(θ)-cos(θ)-4=0 ?

The general solution for 3cos^2(θ)-cos(θ)-4=0 is θ=pi+2pin

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3cos^2(θ)-cos(θ)-4=0

3 cos^{2} (θ) - cos (θ) - 4 = 0

θ = π + 2 πn

Solution steps

3 cos^{2} (θ) - cos (θ) - 4 = 0

Solve by substitution

cos (θ) = \frac{4}{3}, cos (θ) = - 1

cos (θ) = \frac{4}{3} :

No Solution

cos (θ) = - 1 : θ = π + 2 πn

Combine all the solutions

θ = π + 2 πn

sin (x) = \frac{120 \cdot sin ( 8 )}{30}

sin (θ) = (5)

cos^{2} (x) - 3 cos (x) - 2 = 0

tan (4 x) = tan (2 x)

x, cos (2 x + 5 x) = cos (H x)

What is the general solution for 3cos^2(θ)-cos(θ)-4=0 ?
The general solution for 3cos^2(θ)-cos(θ)-4=0 is θ=pi+2pin