What is the general solution for tan^2(x)-4tan(x)+1=0 ?

The general solution for tan^2(x)-4tan(x)+1=0 is x=1.30899…+pin,x=0.26179…+pin

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tan^2(x)-4tan(x)+1=0

tan^{2} (x) - 4 tan (x) + 1 = 0

x = 1.30899 \dots + πn, x = 0.26179 \dots + πn

Solution steps

tan^{2} (x) - 4 tan (x) + 1 = 0

Solve by substitution

tan (x) = 2 + 3, tan (x) = 2 - 3

tan (x) = 2 + 3 : x = arctan (2 + 3) + πn

tan (x) = 2 - 3 : x = arctan (2 - 3) + πn

Combine all the solutions

x = arctan (2 + 3) + πn, x = arctan (2 - 3) + πn

Show solutions in decimal form

x = 1.30899 \dots + πn, x = 0.26179 \dots + πn

sec (θ) + cos (θ) = sin (θ) tan (θ)

cos (x) = 0.98

tan (3 x + \frac{π}{2}) = - 1

15 = 60 sin (\frac{π}{15 [ 0 - d ]}) + 75

cos (θ) = \frac{2 5}{58}

What is the general solution for tan^2(x)-4tan(x)+1=0 ?
The general solution for tan^2(x)-4tan(x)+1=0 is x=1.30899…+pin,x=0.26179…+pin