What is the general solution for 15=60sin(pi/(15[0-d]))+75 ?

The general solution for 15=60sin(pi/(15[0-d]))+75 is d=-2/(15(4n+3));\quad n\ne-3/4

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15=60sin(pi/(15[0-d]))+75

15 = 60 sin (\frac{π}{15 [ 0 - d ]}) + 75

d = - \frac{2}{15 ( 4 n + 3 )}; n \neq = - \frac{3}{4}

Solution steps

15 = 60 sin (\frac{π}{15 [ 0 - d ]}) + 75

Switch sides

60 sin (\frac{π}{15 [ 0 - d ]}) + 75 = 15

Move

75

to the right side

60 sin (\frac{π}{15 [ 0 - d ]}) = - 60

Divide both sides by

60

sin (\frac{π}{15 [ 0 - d ]}) = - 1

General solutions for

sin (\frac{π}{15 [ 0 - d ]}) = - 1

\frac{π}{15 [ 0 - d ]} = \frac{3 π}{2} + 2 πn

Solve

\frac{π}{15 [ 0 - d ]} = \frac{3 π}{2} + 2 πn : d = - \frac{2}{15 ( 4 n + 3 )}; n \neq = - \frac{3}{4}

d = - \frac{2}{15 ( 4 n + 3 )}; n \neq = - \frac{3}{4}

cos (θ) = \frac{2 5}{58}

tan (θ) = \frac{m ^{2} - m ^{1}}{1 + m ^{2} \cdot m ^{1}}, m^{2}

0 = - 1 - tan^{2} (θ) + 2 tan (θ)

u, x = tanh (u)

3 + 2 cos (x) = 0

What is the general solution for 15=60sin(pi/(15[0-d]))+75 ?
The general solution for 15=60sin(pi/(15[0-d]))+75 is d=-2/(15(4n+3));\quad n\ne-3/4