What is the general solution for sin(x)+sin(90-x)=sin(90) ?

The general solution for sin(x)+sin(90-x)=sin(90) is x=90+360n,x=360+360n

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sin(x)+sin(90-x)=sin(90)

sin (x) + sin (9 0^{\circ} - x) = sin (9 0^{\circ})

x = 9 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) + sin (9 0^{\circ} - x) = sin (9 0^{\circ})

sin (9 0^{\circ}) = 1

sin (x) + sin (9 0^{\circ} - x) = 1

Rewrite using trig identities

2 cos (\frac{4 x - 18 0 ^{\circ}}{4}) = 1

Divide both sides by

2

cos (\frac{4 x - 18 0 ^{\circ}}{4}) = \frac{2}{2}

General solutions for

cos (\frac{4 x - 18 0 ^{\circ}}{4}) = \frac{2}{2}

\frac{4 x - 18 0 ^{\circ}}{4} = 4 5^{\circ} + 36 0^{\circ} n, \frac{4 x - 18 0 ^{\circ}}{4} = 31 5^{\circ} + 36 0^{\circ} n

Solve

\frac{4 x - 18 0 ^{\circ}}{4} = 4 5^{\circ} + 36 0^{\circ} n : x = 9 0^{\circ} + 36 0^{\circ} n

Solve

\frac{4 x - 18 0 ^{\circ}}{4} = 31 5^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} + 36 0^{\circ} n

x = 9 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} + 36 0^{\circ} n

sin (x) - 2 cos (x) cot (x) = csc (x)

sin (2 x) = cos (x - 6 0^{\circ})

tan (18 0^{\circ} - θ) = 33

tan (x) = \frac{1}{cos ^{2} ( x )}

arccsc (2 x) = \frac{π}{6}

What is the general solution for sin(x)+sin(90-x)=sin(90) ?
The general solution for sin(x)+sin(90-x)=sin(90) is x=90+360n,x=360+360n