What is the general solution for 3tan^2(θ)+sqrt(3)tan(θ)=0,0<= θ<= 360 ?

The general solution for 3tan^2(θ)+sqrt(3)tan(θ)=0,0<= θ<= 360 is θ=0,θ=180,θ=360,θ=150,θ=330

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3tan^2(θ)+sqrt(3)tan(θ)=0,0<= θ<= 360

3 tan^{2} (θ) + 3 tan (θ) = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}, θ = 15 0^{\circ}, θ = 33 0^{\circ}

Solution steps

3 tan^{2} (θ) + 3 tan (θ) = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

Solve by substitution

tan (θ) = 0, tan (θ) = - \frac{3}{3}

tan (θ) = 0, 0 \leq θ \leq 36 0^{\circ} : θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}

tan (θ) = - \frac{3}{3}, 0 \leq θ \leq 36 0^{\circ} : θ = 15 0^{\circ}, θ = 33 0^{\circ}

Combine all the solutions

θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}, θ = 15 0^{\circ}, θ = 33 0^{\circ}

cos (a) = \frac{24}{25}

sin^{2} (x) = 3 sin (x) - 2

4 sin^{2} (3 x) - 1 = 0

sin (θ) - 2 cos^{2} (θ) = - 1

\frac{1}{1 - cos ( x )} + \frac{1}{1 + cos ( x )} = 2 csc (x)

What is the general solution for 3tan^2(θ)+sqrt(3)tan(θ)=0,0<= θ<= 360 ?
The general solution for 3tan^2(θ)+sqrt(3)tan(θ)=0,0<= θ<= 360 is θ=0,θ=180,θ=360,θ=150,θ=330