What is the general solution for 2sqrt(3)sin(2θ)=sqrt(3) ?

The general solution for 2sqrt(3)sin(2θ)=sqrt(3) is θ= pi/(12)+pin,θ=(5pi)/(12)+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sqrt(3)sin(2θ)=sqrt(3)

23 sin (2 θ) = 3

θ = \frac{π}{12} + πn, θ = \frac{5 π}{12} + πn

Solution steps

23 sin (2 θ) = 3

Divide both sides by

23

sin (2 θ) = \frac{1}{2}

General solutions for

sin (2 θ) = \frac{1}{2}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{5 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{5 π}{12} + πn

0 = 3 - 2 sin (x)

- 2 sin^{2} (θ) + cos (θ) = - 1

4 cos (θ) = 4 (1 - cos (θ))

2 cos (x) = 1.7

sin (2 x + 30) = 0.8

What is the general solution for 2sqrt(3)sin(2θ)=sqrt(3) ?
The general solution for 2sqrt(3)sin(2θ)=sqrt(3) is θ= pi/(12)+pin,θ=(5pi)/(12)+pin