What is the general solution for sin(b)=(sqrt(2))/2 ?

The general solution for sin(b)=(sqrt(2))/2 is b= pi/4+2pin,b=(3pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(b)=(sqrt(2))/2

sin (b) = \frac{2}{2}

b = \frac{π}{4} + 2 πn, b = \frac{3 π}{4} + 2 πn

Solution steps

sin (b) = \frac{2}{2}

General solutions for

sin (b) = \frac{2}{2}

b = \frac{π}{4} + 2 πn, b = \frac{3 π}{4} + 2 πn

h = 7 cos (\frac{π}{3} t), t

3 + 3 sin (θ) = 3 + 3 cos (θ)

- 3 = tan (θ)

cot (θ) = 13

arctan (0.2 x) + arctan (0.0625 x) = 5 4^{\circ}

What is the general solution for sin(b)=(sqrt(2))/2 ?
The general solution for sin(b)=(sqrt(2))/2 is b= pi/4+2pin,b=(3pi)/4+2pin