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Popular >

-sin(A)+2cos(A)sin(A)=0

Solution

- sin (A) + 2 cos (A) sin (A) = 0

Solution

A = 2 πn, A = π + 2 πn, A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

+1

Solution steps

- sin (A) + 2 cos (A) sin (A) = 0

Factor

- sin (A) + 2 cos (A) sin (A) : sin (A) (2 cos (A) - 1)

sin (A) (2 cos (A) - 1) = 0

Solving each part separately

sin (A) = 0 or 2 cos (A) - 1 = 0

sin (A) = 0 : A = 2 πn, A = π + 2 πn

2 cos (A) - 1 = 0 : A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

Combine all the solutions

A = 2 πn, A = π + 2 πn, A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

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Frequently Asked Questions (FAQ)

What is the general solution for -sin(A)+2cos(A)sin(A)=0 ?
The general solution for -sin(A)+2cos(A)sin(A)=0 is A=2pin,A=pi+2pin,A= pi/3+2pin,A=(5pi)/3+2pin