What is the general solution for tan(5θ+30)=1 ?

The general solution for tan(5θ+30)=1 is θ=-6+(pin)/5+pi/(20)

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tan(5θ+30)=1

tan (5 θ + 30) = 1

θ = - 6 + \frac{πn}{5} + \frac{π}{20}

Solution steps

tan (5 θ + 30) = 1

General solutions for

tan (5 θ + 30) = 1

5 θ + 30 = \frac{π}{4} + πn

Solve

5 θ + 30 = \frac{π}{4} + πn : θ = - 6 + \frac{πn}{5} + \frac{π}{20}

θ = - 6 + \frac{πn}{5} + \frac{π}{20}

885 cos (θ) - 70 = cos (25 0^{\circ})

tan (x) + 5 = 0, x \leq 0 < 2 π

\frac{31.5}{sin ( 57.2 2 ^{\circ} )} = \frac{24.4}{sin ( x )}

23 cos (θ - \frac{π}{3}) = 3, 0 \leq θ \leq 2 π

sin (6 x) = 1

What is the general solution for tan(5θ+30)=1 ?
The general solution for tan(5θ+30)=1 is θ=-6+(pin)/5+pi/(20)