What is the general solution for -1=sec(θ) ?

The general solution for -1=sec(θ) is θ=pi+2pin

-1=sec(θ)

- 1 = sec (θ)

θ = π + 2 πn

Degrees

θ = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- 1 = sec (θ)

Switch sides

sec (θ) = - 1

General solutions for

sec (θ) = - 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

θ = π + 2 πn

θ = π + 2 πn

\frac{sin ( 11 5 ^{\circ} )}{20} = \frac{sin ( b )}{11}

cos (θ) = \frac{25}{714}

3 sec^{2} (x) - 4 = 0, 0 \leq x < 2 π

3 cos (2 x) + 7 sin (x) - 5 = 0

cos^{2} (θ) = \frac{1}{3}

What is the general solution for -1=sec(θ) ?
The general solution for -1=sec(θ) is θ=pi+2pin