What is the general solution for 2sec(θ)+4=0 ?

The general solution for 2sec(θ)+4=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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2sec(θ)+4=0

2 sec (θ) + 4 = 0

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

2 sec (θ) + 4 = 0

Move

4

to the right side

2 sec (θ) = - 4

Divide both sides by

2

sec (θ) = - 2

General solutions for

sec (θ) = - 2

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin (x) = \frac{( 60 \cdot sin ( 15 5 ^{\circ} ) )}{97.72}

(1 - 2 cos (x)) (1 + sin (x)) = 0

3 cos (2 x) + 7 sin (x) - 5 = 0

cos^{2} (θ) = \frac{1}{3}

x, sin (\frac{x}{5}) = - \frac{3}{2}

What is the general solution for 2sec(θ)+4=0 ?
The general solution for 2sec(θ)+4=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin