What is the general solution for (tan(x)-1)(cos(x)-1)=0 ?

The general solution for (tan(x)-1)(cos(x)-1)=0 is x= pi/4+pin,x=2pin

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(tan(x)-1)(cos(x)-1)=0

(tan (x) - 1) (cos (x) - 1) = 0

x = \frac{π}{4} + πn, x = 2 πn

Solution steps

(tan (x) - 1) (cos (x) - 1) = 0

Solving each part separately

tan (x) - 1 = 0 or cos (x) - 1 = 0

tan (x) - 1 = 0 : x = \frac{π}{4} + πn

cos (x) - 1 = 0 : x = 2 πn

Combine all the solutions

x = \frac{π}{4} + πn, x = 2 πn

sin (y) = \frac{4}{12}

x, 2 y sin (x) = 0

2 sin^{2} (\frac{θ}{2}) - 2 cos^{2} (θ) = 0

- 14 sin (x) + 14 cos (2 x) = 0

2 cos (2 x) + 2 = 0, 0 \leq x \leq 2 π

What is the general solution for (tan(x)-1)(cos(x)-1)=0 ?
The general solution for (tan(x)-1)(cos(x)-1)=0 is x= pi/4+pin,x=2pin