What is the general solution for sin(2x)=1-sin(2x) ?

The general solution for sin(2x)=1-sin(2x) is x= pi/(12)+pin,x=(5pi)/(12)+pin

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sin(2x)=1-sin(2x)

sin (2 x) = 1 - sin (2 x)

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

sin (2 x) = 1 - sin (2 x)

Solve by substitution

sin (2 x) = \frac{1}{2}

sin (2 x) = \frac{1}{2} : x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Combine all the solutions

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

3 tan (c) + 8 = 0

cos^{2} (x) - 2 cos (x) - 2 = 0

tan (x) = \frac{14.9}{13.3}

3 sin^{2} (x) + sin (x) - 4 = 0, 0 \leq x \leq 2 π

sin (θ) + 2 = 0

What is the general solution for sin(2x)=1-sin(2x) ?
The general solution for sin(2x)=1-sin(2x) is x= pi/(12)+pin,x=(5pi)/(12)+pin