What is the general solution for cos(2pix)=0 ?

The general solution for cos(2pix)=0 is x= 1/4+n,x= 3/4+n

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cos(2pix)=0

cos (2 π x) = 0

x = \frac{1}{4} + n, x = \frac{3}{4} + n

Solution steps

cos (2 π x) = 0

General solutions for

cos (2 π x) = 0

2 π x = \frac{π}{2} + 2 πn, 2 π x = \frac{3 π}{2} + 2 πn

Solve

2 π x = \frac{π}{2} + 2 πn : x = \frac{1}{4} + n

Solve

2 π x = \frac{3 π}{2} + 2 πn : x = \frac{3}{4} + n

x = \frac{1}{4} + n, x = \frac{3}{4} + n

sin (2 x) = 0.8, - 18 0^{\circ} \leq x \leq 18 0^{\circ}

\frac{tan ( x )}{1 + tan ( x )} = 0

1 - cos (x) + sin (x) = 0

\frac{12000}{2 \cdot 6380} = tan (\frac{9 0 ^{\circ} - u}{2})

cos^{2} (t) - 3 sin (t) = 3

What is the general solution for cos(2pix)=0 ?
The general solution for cos(2pix)=0 is x= 1/4+n,x= 3/4+n