What is the general solution for 2sin^2(t)cos(t)=0 ?

The general solution for 2sin^2(t)cos(t)=0 is t=2pin,t=pi+2pin,t= pi/2+2pin,t=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(t)cos(t)=0

2 sin^{2} (t) cos (t) = 0

t = 2 πn, t = π + 2 πn, t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (t) cos (t) = 0

Solving each part separately

sin^{2} (t) = 0 or cos (t) = 0

sin^{2} (t) = 0 : t = 2 πn, t = π + 2 πn

cos (t) = 0 : t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Combine all the solutions

t = 2 πn, t = π + 2 πn, t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

2 cos (θ) + sin (θ) = 0

2 sin^{2} (x) + sin (x) - 1 = 0, 0 < x < 2 π

5 sin (x) - 12 cos (x) = 13

sec (x) = 1.562641

cos (a) = - \frac{1}{2}

What is the general solution for 2sin^2(t)cos(t)=0 ?
The general solution for 2sin^2(t)cos(t)=0 is t=2pin,t=pi+2pin,t= pi/2+2pin,t=(3pi)/2+2pin