What is the general solution for 0=4sin(4x+3pi) ?

The general solution for 0=4sin(4x+3pi) is x=(pin)/2-(3pi)/4 ,x=-pi/2+(pin)/2

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0=4sin(4x+3pi)

0 = 4 sin (4 x + 3 π)

x = \frac{πn}{2} - \frac{3 π}{4}, x = - \frac{π}{2} + \frac{πn}{2}

Solution steps

0 = 4 sin (4 x + 3 π)

Switch sides

4 sin (4 x + 3 π) = 0

Divide both sides by

4

sin (4 x + 3 π) = 0

General solutions for

sin (4 x + 3 π) = 0

4 x + 3 π = 0 + 2 πn, 4 x + 3 π = π + 2 πn

Solve

4 x + 3 π = 0 + 2 πn : x = \frac{πn}{2} - \frac{3 π}{4}

Solve

4 x + 3 π = π + 2 πn : x = - \frac{π}{2} + \frac{πn}{2}

x = \frac{πn}{2} - \frac{3 π}{4}, x = - \frac{π}{2} + \frac{πn}{2}

0.5 = 1 - sin (θ)

θ, r = 6 sin (2 θ)

1.5 sin (3 0^{\circ}) = sin (x)

3 sin (x) - 3 cos (x) = 6

tan (θ) = \frac{11}{100}

What is the general solution for 0=4sin(4x+3pi) ?
The general solution for 0=4sin(4x+3pi) is x=(pin)/2-(3pi)/4 ,x=-pi/2+(pin)/2