What is the general solution for 27tan^2(x)-9=0 ?

The general solution for 27tan^2(x)-9=0 is x=0.52359…+pin,x=-0.52359…+pin

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27tan^2(x)-9=0

27 tan^{2} (x) - 9 = 0

x = 0.52359 \dots + πn, x = - 0.52359 \dots + πn

Solution steps

27 tan^{2} (x) - 9 = 0

Solve by substitution

tan (x) = \frac{1}{3}, tan (x) = - \frac{1}{3}

tan (x) = \frac{1}{3} : x = arctan (\frac{1}{3}) + πn

tan (x) = - \frac{1}{3} : x = arctan (- \frac{1}{3}) + πn

Combine all the solutions

x = arctan (\frac{1}{3}) + πn, x = arctan (- \frac{1}{3}) + πn

Show solutions in decimal form

x = 0.52359 \dots + πn, x = - 0.52359 \dots + πn

tan (x) = \frac{8}{17}

sin (x - 9 0^{\circ}) = cos (x)

cos (x) = \frac{67}{77}

(sin (x) + cos (x))^{2} = \frac{1 + 2 sin ( x )}{sec ( x )}

cot (\frac{π}{3}) = tan (x)

What is the general solution for 27tan^2(x)-9=0 ?
The general solution for 27tan^2(x)-9=0 is x=0.52359…+pin,x=-0.52359…+pin