What is the general solution for sin^2(x)+1=3sin(x)-1 ?

The general solution for sin^2(x)+1=3sin(x)-1 is x= pi/2+2pin

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sin^2(x)+1=3sin(x)-1

sin^{2} (x) + 1 = 3 sin (x) - 1

x = \frac{π}{2} + 2 πn

Solution steps

sin^{2} (x) + 1 = 3 sin (x) - 1

Solve by substitution

sin (x) = 2, sin (x) = 1

sin (x) = 2 :

No Solution

sin (x) = 1 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn

2 tan (θ) = sec^{2} (θ)

tan (θ) = \frac{14}{15}

sin (2 x) + cos (2 x) = - 1

sin (- θ) = - \frac{3}{5}, tan (θ) > 0

tan^{3} (x) + tan^{2} (x) - 3 tan (x) - 3 = 0

What is the general solution for sin^2(x)+1=3sin(x)-1 ?
The general solution for sin^2(x)+1=3sin(x)-1 is x= pi/2+2pin