What is the general solution for sin(2x)+cos(2x)=-1 ?

The general solution for sin(2x)+cos(2x)=-1 is x=pin+pi/2 ,x=pin+(3pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2x)+cos(2x)=-1

sin (2 x) + cos (2 x) = - 1

x = πn + \frac{π}{2}, x = πn + \frac{3 π}{4}

Solution steps

sin (2 x) + cos (2 x) = - 1

Rewrite using trig identities

2 sin (2 x + \frac{π}{4}) = - 1

Divide both sides by

2

sin (2 x + \frac{π}{4}) = - \frac{2}{2}

General solutions for

sin (2 x + \frac{π}{4}) = - \frac{2}{2}

2 x + \frac{π}{4} = \frac{5 π}{4} + 2 πn, 2 x + \frac{π}{4} = \frac{7 π}{4} + 2 πn

Solve

2 x + \frac{π}{4} = \frac{5 π}{4} + 2 πn : x = πn + \frac{π}{2}

Solve

2 x + \frac{π}{4} = \frac{7 π}{4} + 2 πn : x = πn + \frac{3 π}{4}

x = πn + \frac{π}{2}, x = πn + \frac{3 π}{4}

sin (- θ) = - \frac{3}{5}, tan (θ) > 0

tan^{3} (x) + tan^{2} (x) - 3 tan (x) - 3 = 0

tan^{2} (x) + 5 = 3 sec^{2} (x)

tan (x) = \frac{7}{2}

6 cos^{2} (2 x) + 10 cos (4 x) = 12.05718

What is the general solution for sin(2x)+cos(2x)=-1 ?
The general solution for sin(2x)+cos(2x)=-1 is x=pin+pi/2 ,x=pin+(3pi)/4