What is the general solution for 4sin(A)+3=2sin(A)+4 ?

The general solution for 4sin(A)+3=2sin(A)+4 is A= pi/6+2pin,A=(5pi)/6+2pin

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4sin(A)+3=2sin(A)+4

4 sin (A) + 3 = 2 sin (A) + 4

A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

Solution steps

4 sin (A) + 3 = 2 sin (A) + 4

Solve by substitution

sin (A) = \frac{1}{2}

sin (A) = \frac{1}{2} : A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

Combine all the solutions

A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

0 = - 18 cos (3 x)

cos^{2} (2 x) - 3 cos (2 x) = 0

csc^{2} (x) = sin (x)

cos (θ) = \frac{4}{7}, tan (θ) < 0

tan (θ) = \frac{4}{2}

What is the general solution for 4sin(A)+3=2sin(A)+4 ?
The general solution for 4sin(A)+3=2sin(A)+4 is A= pi/6+2pin,A=(5pi)/6+2pin