What is the general solution for 1-2cos^2(x)=0,0<= x<= 2pi ?

The general solution for 1-2cos^2(x)=0,0<= x<= 2pi is x= pi/4 ,x=(7pi)/4 ,x=(3pi)/4 ,x=(5pi)/4

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1-2cos^2(x)=0,0<= x<= 2pi

1 - 2 cos^{2} (x) = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{7 π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}

Solution steps

1 - 2 cos^{2} (x) = 0, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - \frac{1}{2}

cos (x) = \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{π}{4}, x = \frac{7 π}{4}

cos (x) = - \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{3 π}{4}, x = \frac{5 π}{4}

Combine all the solutions

x = \frac{π}{4}, x = \frac{7 π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}

2 sin (x - 2 0^{\circ}) + 1 = 0

9.2 cos (x) = 6.3

sec (x) + 3 tan (x) = 1 + 2 tan (x)

2 sin (3 x) = 0

x, cos (x) - sin (x + y) = 0

What is the general solution for 1-2cos^2(x)=0,0<= x<= 2pi ?
The general solution for 1-2cos^2(x)=0,0<= x<= 2pi is x= pi/4 ,x=(7pi)/4 ,x=(3pi)/4 ,x=(5pi)/4