What is the general solution for cos(4+x)=0.45 ?

The general solution for cos(4+x)=0.45 is x=1.10403…+2pin-4,x=2pi-1.10403…+2pin-4

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cos(4+x)=0.45

cos (4 + x) = 0.45

x = 1.10403 \dots + 2 πn - 4, x = 2 π - 1.10403 \dots + 2 πn - 4

Solution steps

cos (4 + x) = 0.45

Apply trig inverse properties

4 + x = arccos (0.45) + 2 πn, 4 + x = 2 π - arccos (0.45) + 2 πn

Solve

4 + x = arccos (0.45) + 2 πn : x = arccos (0.45) + 2 πn - 4

Solve

4 + x = 2 π - arccos (0.45) + 2 πn : x = 2 π - arccos (0.45) + 2 πn - 4

x = arccos (0.45) + 2 πn - 4, x = 2 π - arccos (0.45) + 2 πn - 4

Show solutions in decimal form

x = 1.10403 \dots + 2 πn - 4, x = 2 π - 1.10403 \dots + 2 πn - 4

(tan (θ) - 2) (16 sin^{2} (θ) - 1) = 0

csc (θ) = 1.9

4 cos^{2} (x) = 4 - 2 sin^{2} (x)

sin (x) = 2 cos (\frac{x}{2})

2 sin (x) + \frac{1}{sin ( x )} = 3

What is the general solution for cos(4+x)=0.45 ?
The general solution for cos(4+x)=0.45 is x=1.10403…+2pin-4,x=2pi-1.10403…+2pin-4