What is the general solution for tan(2x-n/4)=-1,0<x<= 360 ?

The general solution for tan(2x-n/4)=-1,0<x<= 360 is No Solution for x\in\mathbb{R}

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tan(2x-n/4)=-1,0<x<= 360

tan (2 x - \frac{n}{4}) = - 1, 0^{\circ} < x \leq 36 0^{\circ}

No Solution for x \in R

Solution steps

tan (2 x - \frac{n}{4}) = - 1, 0^{\circ} < x \leq 36 0^{\circ}

General solutions for

tan (2 x - \frac{n}{4}) = - 1

2 x - \frac{n}{4} = 13 5^{\circ} + 18 0^{\circ} n

Solve

2 x - \frac{n}{4} = 13 5^{\circ} + 18 0^{\circ} k : x = \frac{54 0 ^{\circ} + n}{8} + \frac{18 0 ^{\circ} k}{2}

x = \frac{54 0 ^{\circ} + n}{8} + \frac{18 0 ^{\circ} k}{2}

Solutions for the range

0 < x \leq 36 0^{\circ}

No Solution for x \in R

2 sin^{2} (θ) = cos^{2} (θ)

- cos (x) = - sin^{2} (x) - 1, (0, 2 π)

x, y + arctan (\frac{y}{x}) = 0

tan (θ) = - 1, 0 \leq θ \leq 2 π

0.85 = \frac{1 - sin ( x )}{1 + sin ( x )}

What is the general solution for tan(2x-n/4)=-1,0<x<= 360 ?
The general solution for tan(2x-n/4)=-1,0<x<= 360 is No Solution for x\in\mathbb{R}