What is the general solution for cos(x)tan(x)-sin^2(x)=0 ?

The general solution for cos(x)tan(x)-sin^2(x)=0 is x=2pin,x=pi+2pin

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cos(x)tan(x)-sin^2(x)=0

cos (x) tan (x) - sin^{2} (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

cos (x) tan (x) - sin^{2} (x) = 0

Rewrite using trig identities

sin (x) - sin^{2} (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 1 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

x = 2 πn, x = π + 2 πn

t, y^{11} + 9 y = 18 cos (3 t)

tan (x) = \frac{0.75}{6}

2 sec (x) - 2 = 0

(tan (x)) (sin^{2} (x) - a) (sec (x) - a) = 0

3 cos (x) + 2 sin (x) = 3

What is the general solution for cos(x)tan(x)-sin^2(x)=0 ?
The general solution for cos(x)tan(x)-sin^2(x)=0 is x=2pin,x=pi+2pin