What is the general solution for cos(x)+2cos^2(x)=1 ?

The general solution for cos(x)+2cos^2(x)=1 is x= pi/3+2pin,x=(5pi)/3+2pin,x=pi+2pin

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cos(x)+2cos^2(x)=1

cos (x) + 2 cos^{2} (x) = 1

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = π + 2 πn

Solution steps

cos (x) + 2 cos^{2} (x) = 1

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - 1

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = π + 2 πn

t, 0.08 = 0.1 cos (4 t)

- \frac{2}{3} = cos (x)

ϕ, (x cos (ϕ))^{2} = x^{2} sin^{2} (ϕ) (1)

cos (18 0^{\circ} - x) = sin (- 30 0^{\circ})

sin^{2} (x) = \frac{( 6 m - 5 )}{8}

What is the general solution for cos(x)+2cos^2(x)=1 ?
The general solution for cos(x)+2cos^2(x)=1 is x= pi/3+2pin,x=(5pi)/3+2pin,x=pi+2pin