What is the general solution for tan^2(4(x+pi/2))=3 ?

The general solution for tan^2(4(x+pi/2))=3 is x=(-5pi+3pin)/(12),x=(-4pi+3pin)/(12)

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tan^2(4(x+pi/2))=3

tan^{2} (4 (x + \frac{π}{2})) = 3

x = \frac{- 5 π + 3 πn}{12}, x = \frac{- 4 π + 3 πn}{12}

Solution steps

tan^{2} (4 (x + \frac{π}{2})) = 3

Solve by substitution

tan (4 (x + \frac{π}{2})) = 3, tan (4 (x + \frac{π}{2})) = - 3

tan (4 (x + \frac{π}{2})) = 3 : x = \frac{- 5 π + 3 πn}{12}

tan (4 (x + \frac{π}{2})) = - 3 : x = \frac{- 4 π + 3 πn}{12}

Combine all the solutions

x = \frac{- 5 π + 3 πn}{12}, x = \frac{- 4 π + 3 πn}{12}

sin (9 x + 2) = cos (6 x - 7)

2 cos (3 x + \frac{π}{2}) = - 1

sin (\frac{3 θ}{2}) = 0

4 sin (\frac{π}{2} x) = 3

1 + cos (θ) = 2 cos (θ)

What is the general solution for tan^2(4(x+pi/2))=3 ?
The general solution for tan^2(4(x+pi/2))=3 is x=(-5pi+3pin)/(12),x=(-4pi+3pin)/(12)