What is the general solution for 1=2cos(3x) ?

The general solution for 1=2cos(3x) is x= pi/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3

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1=2cos(3x)

1 = 2 cos (3 x)

x = \frac{π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

Solution steps

1 = 2 cos (3 x)

Switch sides

2 cos (3 x) = 1

Divide both sides by

2

cos (3 x) = \frac{1}{2}

General solutions for

cos (3 x) = \frac{1}{2}

3 x = \frac{π}{3} + 2 πn, 3 x = \frac{5 π}{3} + 2 πn

Solve

3 x = \frac{π}{3} + 2 πn : x = \frac{π}{9} + \frac{2 πn}{3}

Solve

3 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

sec (b) = \frac{1}{2}

2 cos (2 x) = sin (2 x)

0.322 = sin (3.92232 \cdot t)

cos (x) tan^{2} (x) = 3 cos (x), 0 \leq x < 2 π

2 - cos (2 x) + 1 = 0

What is the general solution for 1=2cos(3x) ?
The general solution for 1=2cos(3x) is x= pi/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3