What is the general solution for cos(θ)=0.3,cos(2θ) ?

The general solution for cos(θ)=0.3,cos(2θ) is No Solution for θ\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)=0.3,cos(2θ)

cos (θ) = 0.3, cos (2 θ)

No Solution for θ \in R

Solution steps

cos (θ) = 0.3, cos (2 θ)

Apply trig inverse properties

θ = arccos (0.3) + 2 πn, θ = 2 π - arccos (0.3) + 2 πn

Solutions for the range

cos (2 θ)

No Solution for θ \in R

(- \frac{2}{3})^{2} + 1 = sec (θ)

1 = sech^{2} (x)

tan (θ) = 0.86667

sin (x) \cdot cos^{2} (x) = 1

t, f w = 2 + cos (10 π t)

What is the general solution for cos(θ)=0.3,cos(2θ) ?
The general solution for cos(θ)=0.3,cos(2θ) is No Solution for θ\in\mathbb{R}