What is the general solution for sec^2(t)+2sec(t)=0 ?

The general solution for sec^2(t)+2sec(t)=0 is t=(2pi)/3+2pin,t=(4pi)/3+2pin

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sec^2(t)+2sec(t)=0

sec^{2} (t) + 2 sec (t) = 0

t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

Solution steps

sec^{2} (t) + 2 sec (t) = 0

Solve by substitution

sec (t) = 0, sec (t) = - 2

sec (t) = 0 :

No Solution

sec (t) = - 2 : t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

Combine all the solutions

t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

sin (27 0^{\circ} + x) - cos (18 0^{\circ} - x) = - sin (x)

9 cos (3 x) = 0

16 (l) cos (θ) = 5 sin (2 θ) (2 l)

∣ sin (x) ∣ = \frac{2}{π}

2 + cos (2 θ) = 0

What is the general solution for sec^2(t)+2sec(t)=0 ?
The general solution for sec^2(t)+2sec(t)=0 is t=(2pi)/3+2pin,t=(4pi)/3+2pin