What is the general solution for 9cos(3x)=0 ?

The general solution for 9cos(3x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3

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9cos(3x)=0

9 cos (3 x) = 0

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

9 cos (3 x) = 0

Divide both sides by

9

cos (3 x) = 0

General solutions for

cos (3 x) = 0

3 x = \frac{π}{2} + 2 πn, 3 x = \frac{3 π}{2} + 2 πn

Solve

3 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 x = \frac{3 π}{2} + 2 πn : x = \frac{π}{2} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

16 (l) cos (θ) = 5 sin (2 θ) (2 l)

∣ sin (x) ∣ = \frac{2}{π}

2 + cos (2 θ) = 0

cos (\frac{π ( x + 5 )}{3}) = \frac{1}{2}

(sin (x))^{2} + (1 - 2) sin (x) - 2 = 0

What is the general solution for 9cos(3x)=0 ?
The general solution for 9cos(3x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3