What is the general solution for 1-sinh^2(x)=0 ?

The general solution for 1-sinh^2(x)=0 is x=ln(-1+sqrt(2)),x=ln(1+sqrt(2))

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1-sinh^2(x)=0

1 - sinh^{2} (x) = 0

x = ln (- 1 + 2), x = ln (1 + 2)

Solution steps

1 - sinh^{2} (x) = 0

Rewrite using trig identities

1 - (\frac{e ^{x} - e ^{- x}}{2})^{2} = 0

1 - (\frac{e ^{x} - e ^{- x}}{2})^{2} = 0 : x = ln (- 1 + 2), x = ln (1 + 2)

x = ln (- 1 + 2), x = ln (1 + 2)

sin (y + 1 0^{\circ}) = cos (y + 2 0^{\circ})

tan (x) = - 1, 7

tan (θ) (3 cos^{2} (θ) - sin^{2} (θ)) = 0

sin^{3} (x) = cos^{2} (x)

sin (θ) = 2 cos (θ)

What is the general solution for 1-sinh^2(x)=0 ?
The general solution for 1-sinh^2(x)=0 is x=ln(-1+sqrt(2)),x=ln(1+sqrt(2))