What is the general solution for tan(θ)(3cos^2(θ)-sin^2(θ))=0 ?

The general solution for tan(θ)(3cos^2(θ)-sin^2(θ))=0 is θ=pin,θ=(2pi)/3+pin,θ= pi/3+pin

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tan(θ)(3cos^2(θ)-sin^2(θ))=0

tan (θ) (3 cos^{2} (θ) - sin^{2} (θ)) = 0

θ = πn, θ = \frac{2 π}{3} + πn, θ = \frac{π}{3} + πn

Solution steps

tan (θ) (3 cos^{2} (θ) - sin^{2} (θ)) = 0

Solving each part separately

tan (θ) = 0 or 3 cos^{2} (θ) - sin^{2} (θ) = 0

tan (θ) = 0 : θ = πn

3 cos^{2} (θ) - sin^{2} (θ) = 0 : θ = \frac{2 π}{3} + πn, θ = \frac{π}{3} + πn

Combine all the solutions

θ = πn, θ = \frac{2 π}{3} + πn, θ = \frac{π}{3} + πn

sin^{3} (x) = cos^{2} (x)

sin (θ) = 2 cos (θ)

2 cos^{2} (w) + 5 cos (w) + 3 = 0

tan (x) = - 135

3 cos (x) - 4 sin (x) = - 3

What is the general solution for tan(θ)(3cos^2(θ)-sin^2(θ))=0 ?
The general solution for tan(θ)(3cos^2(θ)-sin^2(θ))=0 is θ=pin,θ=(2pi)/3+pin,θ= pi/3+pin