What is the general solution for -4+tan(θ)=(-12-sqrt(3))/3 ?

The general solution for -4+tan(θ)=(-12-sqrt(3))/3 is θ=-0.52359…+pin

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-4+tan(θ)=(-12-sqrt(3))/3

- 4 + tan (θ) = \frac{- 12 - 3}{3}

θ = - 0.52359 \dots + πn

Solution steps

- 4 + tan (θ) = \frac{- 12 - 3}{3}

Move

4

to the right side

tan (θ) = \frac{- 12 - 3}{3} + 4

Apply trig inverse properties

θ = arctan (\frac{- 12 - 3}{3} + 4) + πn

Show solutions in decimal form

θ = - 0.52359 \dots + πn

2 cos^{2} (x) - 3 = 0

2 sin (x) + 3 tan (x) = 0

tan (t) = 2, 0 < t < \frac{π}{2}, cos (t)

\frac{cos ( x ) + sin ( x )}{sin ( x )} = \frac{1}{tan ( x )}

cos (2 x) - 3 sin (- x) - 2 = 0

What is the general solution for -4+tan(θ)=(-12-sqrt(3))/3 ?
The general solution for -4+tan(θ)=(-12-sqrt(3))/3 is θ=-0.52359…+pin