What is the general solution for 0=2cos(2θ) ?

The general solution for 0=2cos(2θ) is θ= pi/4+pin,θ=(3pi)/4+pin

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0=2cos(2θ)

0 = 2 cos (2 θ)

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

0 = 2 cos (2 θ)

Switch sides

2 cos (2 θ) = 0

Divide both sides by

2

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

2 sec^{2} (x) + tan (x) = 8

tan (θ) = \frac{48}{8}

- 2 cos (2 x) = 2 sin (x)

sin (θ) - 0.2 cos (θ) = \frac{7.51}{9.8}

23 = - 6 tan (θ)

What is the general solution for 0=2cos(2θ) ?
The general solution for 0=2cos(2θ) is θ= pi/4+pin,θ=(3pi)/4+pin