What is the general solution for 3sec(2θ)=-sqrt(18) ?

The general solution for 3sec(2θ)=-sqrt(18) is θ=(3pi)/8+pin,θ=(5pi)/8+pin

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3sec(2θ)=-sqrt(18)

3 sec (2 θ) = - 18

θ = \frac{3 π}{8} + πn, θ = \frac{5 π}{8} + πn

Solution steps

3 sec (2 θ) = - 18

18 = 32

3 sec (2 θ) = - 32

Divide both sides by

3

sec (2 θ) = - 2

General solutions for

sec (2 θ) = - 2

2 θ = \frac{3 π}{4} + 2 πn, 2 θ = \frac{5 π}{4} + 2 πn

Solve

2 θ = \frac{3 π}{4} + 2 πn : θ = \frac{3 π}{8} + πn

Solve

2 θ = \frac{5 π}{4} + 2 πn : θ = \frac{5 π}{8} + πn

θ = \frac{3 π}{8} + πn, θ = \frac{5 π}{8} + πn

2 sin^{2} (x) - 2 = cos^{2} (x)

sin (2 θ) = \frac{1}{3}

cos^{2} (θ) = 1 - sin (θ)

1 sin (3 0^{\circ}) = 1.495 sin (x)

e^{2 c o s (x) - 1} = 1

What is the general solution for 3sec(2θ)=-sqrt(18) ?
The general solution for 3sec(2θ)=-sqrt(18) is θ=(3pi)/8+pin,θ=(5pi)/8+pin